Advertisements
Advertisements
प्रश्न
What must be added to 2a3 + 5a – a2 – 6 to get a2 – a – a3 + 1?
बेरीज
Advertisements
उत्तर
We get, the required result by subtracting
2a3 + 5a – a2 – 6 from - a3 + a2 - a + 1
= (- a3 + a2 - a + 1) - (2a3 – a2 + 5a – 6)
= - a3 + a2 - a + 1 - 2a3 + a2 - 5a + 6
= - a3 - 2a3 + a2 + a2 - a - 5a + 1 + 6
= - 3a3 + 2a2 - 6a + 7
shaalaa.com
Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Subtract: 4x2 - 5x2y + y2 from - 3y2 + 5xy2 - 7x2 - 9x2y
The perimeter of a rectangle is 28x3+ 16x2 + 8x + 4. One of its sides is 8x2 + 4x. Find the other side
Simplify: 3(4y - 10) 2(y - 1)
Simplify: 5(x − 4) − 3(x − 4) + 7(x − 4)
Multiply: 5, 3a and 2ab2
Multiply: 6a - 5b and - 2a
Multiply: 4a + 5b and 4a - 5b
Evaluate: (a + 5)(3a - 2)(5a + 1)
Evaluate: (5m - 2n)(5m + 2n)(25m2 + 4n2)
Simplify: `"x" + "x + 2"/3`
