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प्रश्न
What must be added to 2a3 + 5a – a2 – 6 to get a2 – a – a3 + 1?
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उत्तर
We get, the required result by subtracting
2a3 + 5a – a2 – 6 from - a3 + a2 - a + 1
= (- a3 + a2 - a + 1) - (2a3 – a2 + 5a – 6)
= - a3 + a2 - a + 1 - 2a3 + a2 - 5a + 6
= - a3 - 2a3 + a2 + a2 - a - 5a + 1 + 6
= - 3a3 + 2a2 - 6a + 7
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संबंधित प्रश्न
If x = 4a2 + b2 - 6ab; y = 3b2 - 2a2 + 8ab and z = 6a2 + 8b2 - 6ab find: x + y + z
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Copy and complete the following multi-plication:
3xy - 2x2 - 6x
× -5x2y
Copy and complete the following multi-plication:
a + b
× a + b
Evaluate: (a + 5)(3a - 2)(5a + 1)
Simplify: `"k"/2 + "k"/3 + "2k"/5`
Simplify: `"m"/5 - "m - 2"/3 + "m"`
Simplify: `7/30 "of" ("p"/3 + "7p"/15)`
