Advertisements
Advertisements
प्रश्न
What must be added to 2a3 + 5a – a2 – 6 to get a2 – a – a3 + 1?
बेरीज
Advertisements
उत्तर
We get, the required result by subtracting
2a3 + 5a – a2 – 6 from - a3 + a2 - a + 1
= (- a3 + a2 - a + 1) - (2a3 – a2 + 5a – 6)
= - a3 + a2 - a + 1 - 2a3 + a2 - 5a + 6
= - a3 - 2a3 + a2 + a2 - a - 5a + 1 + 6
= - 3a3 + 2a2 - 6a + 7
shaalaa.com
Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Subtract: 4x from 8 - x
Subtract: - 8c from c + 3d
Subtract: 4p + p2 from 3p2 - 8p
Subtract: −xy + yz − zx from xy − yz + xz
Subtract: 4x2 - 5x2y + y2 from - 3y2 + 5xy2 - 7x2 - 9x2y
If x = 4a2 + b2 - 6ab; y = 3b2 - 2a2 + 8ab and z = 6a2 + 8b2 - 6ab find: x + y + z
If m = 9x2 - 4xy + 5y2 and n = - 3x2 + 2xy - y2 find: 2m - n
Simplify: x - (x - y) - y - (y - x)
Multiply: 5, 3a and 2ab2
Evaluate: (5m - 2n)(5m + 2n)(25m2 + 4n2)
