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प्रश्न
By how much does 8x3 – 6x2 + 9x – 10 exceed 4x3 + 2x2 + 7x -3?
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उत्तर
8x3 – 6x2 + 9x – 10 exceeds 4x3 + 2x2 + 7x -3
= (8x3 - 6x2 + 9x - 10) - (4x3 + 2x2 + 7x - 3)
= 8x3 - 6x2 + 9x - 10 - 4x3 + 2x2 + 7x - 3
= 8x3 - 4x3 - 6x2 - 2x2 + 9x - 7x - 10 + 3
= 4x3 - 8x2 + 2x - 7
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संबंधित प्रश्न
Find the excess of 4m2 + 4n2 + 4p2 over m2+ 3n2 – 5p2
By how much is 3x3 – 2x2y + xy2 -y3 less than 4x3 – 3x2y – 7xy2 +2y3
Multiply: 4a + 5b and 4a - 5b
Copy and complete the following multi-plication:
3a + 2b
× - 3xy
Copy and complete the following multi-plication:
3xy - 2x2 - 6x
× -5x2y
Copy and complete the following multi-plication:
3m2 + 6m - 2n
× 5n - 3m
Multiply: 2mnpq, 4mnpq and 5 mnpq
Multiply: pq - pm and p2m
Simplify: `"m"/5 - "m - 2"/3 + "m"`
Simplify: `7/30 "of" ("p"/3 + "7p"/15)`
