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प्रश्न
By how much does 8x3 – 6x2 + 9x – 10 exceed 4x3 + 2x2 + 7x -3?
बेरीज
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उत्तर
8x3 – 6x2 + 9x – 10 exceeds 4x3 + 2x2 + 7x -3
= (8x3 - 6x2 + 9x - 10) - (4x3 + 2x2 + 7x - 3)
= 8x3 - 6x2 + 9x - 10 - 4x3 + 2x2 + 7x - 3
= 8x3 - 4x3 - 6x2 - 2x2 + 9x - 7x - 10 + 3
= 4x3 - 8x2 + 2x - 7
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