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प्रश्न
Simplify: `("p" + "p"/3)("2p" + "p"/2)("3p" - "2p"/3)`
बेरीज
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उत्तर
`("p" + "p"/3)("2p" + "p"/2)("3p" - "2p"/3)`
`= "p" (1 + 1/3)"p"(2 + 1/2)"p"(3 - 2/3)`
`= "p"^3 ((3+1)/3)((4 + 1)/2)((9 - 2)/3)`
`= "p"^3 xx 4/3 xx 5/2 xx 7/3`
`= "p"^3 xx 70/9 = (70"p"^3)/9`
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