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Question
What must be subtracted from a2 + b2 + lab to get – 4ab + 2b2?
Sum
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Solution
We get, the required result by subtracting
– 4ab + 2b2 from a2 + b2 + 2ab
= a2 + b2 + 2ab – (– 4ab + 2b2)
= a2 + b2 + 2ab + 4ab – 2b2
= a2 + b2 – 2b2 + 2ab + 4ab
= a2 – b2 + 6ab
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Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.
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