Advertisements
Advertisements
Question
Find the excess of 4m2 + 4n2 + 4p2 over m2+ 3n2 – 5p2
Advertisements
Solution
The required result will be by substracting
m2+ 3n2 – 5p2 from 4m2 + 4n2 + 4p2
= 4m2 + 4n2 + 4p2 - (m2 + 3n2 - 5p2)
= 4m2 + 4n2 + 4p2 - m2 - 3n2 - 5p2
= 4m2 - m2 + 4n2 - 3n2 + 4p2 + 5p2
= 3m2 + n2 + 9p2
APPEARS IN
RELATED QUESTIONS
Subtract: 2x2 - 7xy - y2 from 3x2 - 5xy + 3y2
What must be added to 2a3 + 5a – a2 – 6 to get a2 – a – a3 + 1?
Simplify: 3x + 5(2x + 6) - 7x
Simplify: 2(x - y) - (x - 8)
Simplify: 4(3x - 8) - 3(5x + 3) - 2(6x - 8)
Copy and complete the following multi-plication:
3xy - 2x2 - 6x
× -5x2y
Copy and complete the following multi-plication:
2a - b + 3c
× 2a - 4b
Evaluate: (a + 1)(a2 - a + 1) and (a - 1)(a2 + a + 1)
Simplify: `"4a"/7 + "2a"/3 - "a"/7`
Simplify: `("p" + "p"/3)("2p" + "p"/2)("3p" - "2p"/3)`
