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प्रश्न
If x = 4a2 + b2 - 6ab; y = 3b2 - 2a2 + 8ab and z = 6a2 + 8b2 - 6ab find: x - y - z
योग
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उत्तर
x = 4a2 + b2 - 6ab
y = 3b2 - 2a2 + 8ab
z = 6a2 + 8b2 - 6ab
x - y - z
= (4a2 + b2 - 6ab) - (3b2 - 2a2 + 8ab) - (6a2 + 8b2 - 6ab)
= 4a2 + b2 - 6ab - 3b2 + 2a2 - 8ab - 6a2 - 8b2 + 6ab
= 4a2 - 2a2 - 6a2 + b2 - 3b2 - 8b2 - 6ab - 8ab + 6ab
= 6a2 - 6a2 + b2 - 11b2 - 14ab + 6ab
= - 10b2 - 8ab
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