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प्रश्न
Subtract: a2 - 3ab - 6b2 from 2b2 - a2 + 2ab
बेरीज
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उत्तर
a2 - 3ab - 6b2 from 2b2 - a2 + 2ab
= (2b2 - a2 + 2ab) - (a2 - 3ab - 6b2)
= 2b2 - a2 + 2ab - a2 + 3ab + 6b2
= - a2 + a2 + 2b2 + 6b2 + 2ab + 3ab
= - 2a2 + 8b2 + 5ab
= 8b2 + 5ab - 2a2
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Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.
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