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Question
What is the magnetization of a bar magnet having a length of 6 cm and the area of cross-section 5 cm2?
Options
1.2 × 10-4 A/m
3.3 × 104 A/m
1.25 × 10-4 A/m
3.3 × 10-4 A/m
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Solution
3.3 × 104 A/m
Explanation:
l = 6 cm, Δ = 5 cm2, M = 1 Am2
magnetization = `"Magnetic moment"/"Volume" = "Am"^2/"m"^3 = "Am"^-1`
= `(1 "Am"^2)/(6 xx 5 "cm"^3) = (1 "Am"^2)/(30 xx 10^-6 "m"^3) = 10^6/30` Am-1
= `1/3 xx 10^5 = 0.33 xx 10^5 = 3.3 xx 10^4` Am-1
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