English

Derive the relation between magnetic field intensity(H) and magnetization(M) for a magnetic material placed in a magnetic field. - Physics

Advertisements
Advertisements

Question

Derive the relation between magnetic field intensity(H) and magnetization(M) for a magnetic material placed in a magnetic field. 

Answer in Brief
Advertisements

Solution

  1. Relation between magnetic field intensity(H) and magnetization(M):
    a. Consider a magnetic material (rod) placed in a magnetizing field (solenoid with n turns per unit length and carrying current I).
    b. The magnetic field inside the solenoid is given by,
    B0 = μ0nI  ….(1)
    Where µ0 = permeability of free space.
    c. The magnetic field inside the rod is given as,
    Bm = µ0M ….(2) 
    Where M = magnetization of the material
    d. The net magnetic field inside the rod is expressed as,
    B = B0 + Bm ….(3)
    ∴ B = µ0nI + µ0M
    ∴ B = µ0H + µ0M
    Where H = nI = Magnetic field intensity
    ∴ B = µ0 (H + M) 
    ∴ H = `"B"/mu_0 - "M"`  ….(4)
    e. Equation (4) shows that the magnetic field (B) induced in the material depends on magnetic field intensity (H) and magnetization (M). 
shaalaa.com
  Is there an error in this question or solution?
Chapter 11: Magnetic materials - Long Answer

APPEARS IN

SCERT Maharashtra Physics [English] 12 Standard HSC
Chapter 11 Magnetic materials
Long Answer | Q 3

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the magnetization of a bar magnet of length 10 cm and cross-sectional area 4 cm2, if the magnetic moment is 2 Am2.


What is Magnetic intensity?


Give two points to distinguish between a paramagnetic and a diamagnetic substance ?


A long, straight wire carries a current i. The magnetising field intensity H is measured at a point P close to the wire. A long, cylindrical iron rod is brought close to the wire, so that the point P is at the centre of the rod. The value of H at P will ______________ .


The magnetic intensity H at the centre of a long solenoid carrying a current of 2.0 A, is found to be 1500 A m−1. Find the number of turns per centimetre of the solenoid.


The magnetic field inside a long solenoid of 50 turns cm−1 is increased from 2.5 × 10−3 T to 2.5 T when an iron core of cross-sectional area 4 cm2 is inserted into it. Find (a) the current in the solenoid (b) the magnetisation I of the core and (c) the pole strength developed in the core.


Answer the following question.
Define the term "Intensity" in the photon picture of electromagnetic radiation.


What is the magnetization of a bar magnet having a length of 6 cm and the area of cross-section 5 cm2?


A magnetic material of susceptibility 3 × 10−4, and magnetic intensity is 4 × 104 Am1. Then The magnetization in the units of Am1 is ______.


A solenoid has a core of material with relative permeability 500 and its windings carry a current of 1 A. The number of turns of the solenoid is 500 per meter. Calculate the magnetization of the material. 


Explain the magnetization of a material. 


The magnetic susceptibility of a paramagnetic material at - 73°C is 0.0075. Its value at - 173°C will be ______.


An electron moves in a circular orbit with uniform speed v. It produces a magnetic field B at the centre of the circle. The radius of the circle is [µ0 = permeability of free space, e = electronic charge]


The magnetic susceptibility is given by ______


A steel wire of length I has a magnetic moment M. It is then bent into a semicircular arc. The new magnetic moment is ______.


Relative permeability of nickel is 550, then its magnetic susceptibility will be ____________.


For an isotropic medium B, µ, H and M, are related as (where B, µ0, H and Mz have their usual meaning in the context of magnetic material) ____________.


A solenoid has core of a material with relative permeability 500 and its windings carry a current of 2 A. The number of turns of the solenoid is 500 per metre. The magnetization of the material is ______.


An iron rod of cross-sectional area 6 sq. cm is placed with its length parallel to a magnetic field of intensity 1200 Alm. The flux through the rod is 60 x 10-4 Wb. The permeability of the rod is ______.


An iron rod is placed parallel to magnetic field of intensity 4000 A/m. The magnetic flux through the rod is 8 x 10-4 Wb and its cross-sectional area is 4 cm2 . The magnetic permeability of the rod in Wb/A - m is ____________.


The magnetic field (B) inside a long solenoid having 'n', turns per unit length and carrying current 'I' when iron core is kept in it is (`mu_0` = permeability of vacuum, `chi` = magnetic susceptibility) ____________.


A magnet of magnetic moment 6 Am2 weighs 65 g. The density of the material of the magnet is 6500 kg/m3. What is the magnetization?


A magnetizing field of 5000 A/m produces a magnetic flux of 4 x 10-5 Wb in an iron rod of cross-sectional area 0.4 cm2. The permeability of the rod in Wb/A-m, is ______.


A cylindrical magnetic rod has length 5 cm and diameter 1 cm. It has uniform magnetization `5.3 xx 10^3 "A"/"m"^3`. Its net magnetic dipole moment is nearly `(pi = 22/7)`.


Assertion: Susceptibility is defined as the ratio of intensity of magnetisation I to magnetic intensity H.

Reason: Greater the value of susceptibility, smaller the value of intensity of magnetisation I.


A particle of charge 'q' and mass 'm' moves in a circular orbit of radius 'r' with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum is ____________.


The magnetic moment produced in a sample of 2 gram is 8 x 10-7 A/m2. lf its density is 4g/cm3, then the magnetization of the sample is ____________.


The variation of intensity of magnetization (I) and applied magnetic field intensity (H) for three magnetic materials A, B, C are shown in the graph. The material A is ____________.


Find the intensity of magnetization of a magnet of moment 4 Am2 which weighs 50 gram. (Density of the material of a magnet = 5000 kg/m3)


Magnetization of a sample is ______.


The magnetic moment produced in a substance of mass 5 gram is 6 x 10-7 Am2 If its density is 5 g/cm3, then intensity of magnetization in `"A"/"m"` will be ____________.


Magnetic intensity is given by ______.


If `vec"H"` = magnetic intensity, `chi` = susceptibility, magnetic moment per unit volume `vec"M"` equals ______.


A bar magnet is cut into two equal halves by a plane parallel to the magnetic axis. Of the following physical quantities the one which remains unchanged is ______.

The ratio of intensity of magnetisation and magnetising field is called ______.

Susceptibility is positive and large for a ______.

If μ0 is absolute permeability of vacuum and μr is relative magnetic permeability of another medium, then permeability μ of the medium is ______.

The magnetic susceptibility for diamagnetic materials is ______.

Among which of the following the magnetic susceptibility does not depend on the temperature?

Magnetic permeability is maximum for ______


What are the dimensions of χ, the magnetic susceptibility? Consider an H-atom. Guess an expression for χ, upto a constant by constructing a quantity of dimensions of χ, out of parameters of the atom: e, m, v, R and µ0. Here, m is the electronic mass, v is electronic velocity, R is Bohr radius. Estimate the number so obtained and compare with the value of |χ| ~ 10–5 for many solid materials.


Define magnetization.


What is magnetic susceptibility?


A bar magnet has length 3 cm, cross-sectional area 2 cm3 and magnetic moment 3 Am2. The intensity of magnetisation of bar magnet is ______.


The magnetization of a bar magnet of length 4 cm, cross-sectional area 1 cm2 and magnetic moment 2 SI units is ______.


For a medium of permeability µ, its magnetic susceptibility x is [µ 0 = permeability of vacuum]


State SI unit of Magnetization.


The magnetic susceptibility of iron is 5499. The relative permeability of iron will be ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×