Advertisements
Advertisements
Question
What happens to the rate constant k and activation energy Ea as the temperature of a chemical reaction is increased? Justify.
Advertisements
Solution
As the temperature of a chemical reaction rises, the rate constant k rises and the activation energy Ea falls.
According to Arrhenius equation
k = `"Ae"^(-"E"_"a"//"RT")`
As a result, the rate constant k rises exponentially as the temperature rises.
APPEARS IN
RELATED QUESTIONS
The rate constant of a first order reaction increases from 4 × 10−2 to 8 × 10−2 when the temperature changes from 27°C to 37°C. Calculate the energy of activation (Ea). (log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021)
The decomposition of A into product has value of k as 4.5 × 103 s−1 at 10°C and energy of activation 60 kJ mol−1. At what temperature would k be 1.5 × 104 s−1?
What is the effect of adding a catalyst on Activation energy (Ea)
During decomposition of an activated complex:
(i) energy is always released
(ii) energy is always absorbed
(iii) energy does not change
(iv) reactants may be formed
Why does the rate of a reaction increase with rise in temperature?
Oxygen is available in plenty in air yet fuels do not burn by themselves at room temperature. Explain.
For an endothermic reaction energy of activation is Ea and enthalpy of reaction ΔH (both of there in KJ moI–1) minimum value of Ea will be ______.
The activation energy in a chemical reaction is defined as ______.
The equation k = `(6.5 xx 10^12 "s"^(-1))"e"^(- 26000 " K"//"T")` is followed for the decomposition of compound A. The activation energy for the reaction is ______ kJ mol-1. (Nearest integer) (Given: R = 8.314 JK-1 mol-1)
A schematic plot of ln Keq versus inverse of temperature for a reaction is shown below

The reaction must be:
