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Maharashtra State BoardSSC (English Medium) 6th Standard

Using the figures given below, frame problems based on profit percent or loss percent. ​Cost price ₹ 2000, selling price ₹ 1900 - Mathematics

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Question

Using the figures given below, frame problems based on profit percent or loss percent.

​Cost price ₹ 2000, selling price ₹ 1900

Sum
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Solution

Problem: Avinash bought a mobile phone for Rs 2000 and sold the same for Rs 1900. Find his loss percent.

Cost price of mobile phone = Rs 2000

Selling price of mobile phone = Rs 1900

Since selling price is less than cost price, so there is a loss.

Loss = Cost Price − Selling price

= 2000 − 1900

= Rs 100

Let x % be the loss suffered by Avinash. Then,

`"x"/100 = "loss"/"cost price" = 100/2000`

`=> "x"/100 xx 100 = 100/2000 xx 100`

⇒ x = 5

∴ Avinash suffered a loss of 5% in this transaction.

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Chapter 13: Profit – Loss - Practice Set 34 [Page 72]

APPEARS IN

Balbharati Mathematics [English] Standard 6 Maharashtra State Board
Chapter 13 Profit – Loss
Practice Set 34 | Q 2 | Page 72
Balbharati Mathematics Integrated [English] Standard 6 Maharashtra State Board
Chapter 13 Profit-Loss
Practice Set 34 | Q 2. | Page 67

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