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Maharashtra State BoardSSC (English Medium) 6th Standard

Using the figures given below, frame problems based on profit percent or loss percent. Cost price ₹1600, selling price ₹ 2800

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Question

Using the figures given below, frame problems based on profit percent or loss percent.

Cost price ₹1600, selling price ₹ 2800

Sum
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Solution

A man bought an article for Rs 1600 and sold it for Rs 2800. Find his profit percent.

Cost price of an article = Rs 1600

Selling price of an article = Rs 2800

Since selling price is more than cost price, so there is a profit.

Profit = Selling Price − Cost Price

= 2800 − 1600

= Rs 1200

Let x % be the profit made by the man in this transaction. Then,

`"x"/100 = "profit"/"cost price" = 1200/1600`

`"x"/100 = 1200/1600`

`1200/1600 = 12/16 = 3/4`

`x/100 = 3/4`

`x = 3/4 xx 100 = 75`

∴ The man made a profit of 75% in this transaction.

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Chapter 13: Profit – Loss - Practice Set 34 [Page 72]

APPEARS IN

Balbharati Mathematics [English] Standard 6 Maharashtra State Board
Chapter 13 Profit – Loss
Practice Set 34 | Q 1 | Page 72
Balbharati Mathematics Integrated [English] Standard 6 Maharashtra State Board
Chapter 13 Profit-Loss
Practice Set 34 | Q 1. | Page 67

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