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Maharashtra State BoardSSC (English Medium) 6th Standard

Using the figures given below, frame problems based on profit percent or loss percent. ​Cost price of 8 articles is ₹ 1200 each, selling price ₹ 1400 each. - Mathematics

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Question

Using the figures given below, frame problems based on profit percent or loss percent.

​Cost price of 8 articles is ₹ 1200 each, selling price ₹ 1400 each.

Sum
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Solution

Problem: Madanlal bought 8 almirahs each at Rs 1200 and sold them all at Rs 1400 each. What was the percentage of his profit or loss?

Cost price of 1 almirah = Rs 1200

∴ Cost price of 8 almirahs = 8 × 1200 = Rs 9600

Selling price of 1 almirah = Rs 1400

∴ Selling price of 8 almirahs = 8 × 1400 = Rs 11200

Since selling price is more than cost price, then there is a profit.

Profit = Selling Price − Cost Price

= 11200 − 9600

= Rs 1600

Let x % be the Madanlal's profit in this transaction. Then,

`"x"/100 = "Profit"/"cost price" = 1600/9600`

`=> "x"/100 xx 100 = 1600/9600 xx 100`

`=>  "x" = 50/3 = 16 2/3`

∴ Madanlal made a profit of  `16 2/3 %` in this transaction.

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Chapter 13: Profit – Loss - Practice Set 34 [Page 72]

APPEARS IN

Balbharati Mathematics [English] Standard 6 Maharashtra State Board
Chapter 13 Profit – Loss
Practice Set 34 | Q 3 | Page 72
Balbharati Mathematics Integrated [English] Standard 6 Maharashtra State Board
Chapter 13 Profit-Loss
Practice Set 34 | Q 3. | Page 67

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