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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

A shopkeeper gives two successive discounts on an article whose marked price is ₹ 180 and selling price is ₹ 108. Find the first discount percentage if the second discount is 25% - Mathematics

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Question

A shopkeeper gives two successive discounts on an article whose marked price is ₹ 180 and selling price is ₹ 108. Find the first discount percentage if the second discount is 25%

Sum
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Solution

Marked price is given as ₹ 180

Let 1st discount be d1 % = ? ...(to find)

2nd discount be d2 % = 25%

Selling price is 108 ...(given)

Price after 1st discount = `180(1 - ("d"_1)/100)` = P ...(1)

Price after 2nd discount = `"P"_1 (1 - ("d"_2)/100)` = 108

Substituting for P1 from (1), we get

`180(1 - ("d"_1)/100)(1 - ("d"_2)/100)` = 108

⇒ Since d2 = 25, we get

`180(1 - ("d"_1)/100)(1 - 25/100)` = 108

∴ `(1 - ("d"_1)/100) = 108/180 xx 100/75 = 4/5`

`1 - ("d"_1)/100 = 4/5`

∴ `("d"_1)/100 = 1 - 4/5 = 1/5`

∴ d1 = `1/5 xx 100` = 20%

1st discount = 20%

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Chapter 4: Life Mathematics - Exercise 4.5 [Page 152]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 4 Life Mathematics
Exercise 4.5 | Q 11 | Page 152

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