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Question
Using the method of slope, show that the following points are collinear A (16, − 18), B (3, −6), C (−10, 6) .
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Solution
A (16, − 18), B (3, −6), C (−10, 6)
Slope of AB = \[\frac{y_2 - y_1}{x_2 - x_1} = \frac{- 6 + 18}{3 - 16} = - \frac{12}{13}\]
Slope of BC = \[\frac{y_2 - y_1}{x_2 - x_1} = \frac{6 + 6}{- 10 - 3} = - \frac{12}{13}\]
Since, Slope of AB = Slope of BC = \[- \frac{12}{13}\]
Therefore, the given points are collinear.
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