Question

Three resistors are connected to a 12 V battery as shown in the figure given below:

(i) What is the current through the 8 ohm resistor?
(ii) What is the potential difference across the parallel combination of 6 ohm and 12 ohm resistor?
(iii) What is the current through the 6 ohm resistor?

Answer 1

(i) 6 ohm and 12 ohm are connected in parallel, So

⇒ `1/"R"_1 = 1/6 + 1/12 = (2 + 1)/12 = 3/12`

⇒ `1/"R"_1 = 1/4`

R₁ = 4 ohm.

∴ Total Resistance R = 8 + 4 = 12 ohm.

Now ∵ V = IR

⇒ 12 = I × 12

∴ I = 1 Amp.

(ii) V = IR = 1 ×4 = 4 Volt

(iii) ∵ V = I₁R

⇒ 4 = I₁ × 6

∴ I₁ = `4/6`

= 0.66 Amp.