Advertisements
Advertisements
Question
Three heaters each rated 250 W, 100 V are connected in parallel to a 100 V supply of the energy supplied in kWh to the three heaters in 5 hours.
Advertisements
Solution
Given ,
Power , P = 250 W
Voltage , V = 100 V
Time for which energy is supplied , t = 5 h
As , Energy E = P × t
E = 250 × 5 = 1250 Wh
or E = 1.25 kWh
Energy for three heaters = 3 × 1.25 = 3.75 kWh
RELATED QUESTIONS
What is the current in a circuit if the charge passing each point is 20 C in 40 s?
In 10 s, a charge of 25 C leaves a battery, and 200 J of energy are delivered to an outside circuit as a result.
- What is the p.d. across the battery?
- What current flows from the battery?
A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω. How much current would flow through the 12 Ω resistor?
In which of the following cases more electrical energy is consumed per hour?
(i) A current of 1 ampere passed through a resistance of 300 ohms.
(ii) A current of 2 amperes passed through a resistance of 100 ohms.
Tell the odd one out. Give a proper explanation.
In the circuit shown in fig. 6, find the reading of the ammeter A when the switch S is
(a) Opened.
(b) Closed.
State the condition when it is advantageous to connect cells in series.
Give the electric current unit.
Name any two devices, which are working on the heating effect of the electric current.
