Advertisements
Advertisements
प्रश्न
Three heaters each rated 250 W, 100 V are connected in parallel to a 100 V supply of the energy supplied in kWh to the three heaters in 5 hours.
Advertisements
उत्तर
Given ,
Power , P = 250 W
Voltage , V = 100 V
Time for which energy is supplied , t = 5 h
As , Energy E = P × t
E = 250 × 5 = 1250 Wh
or E = 1.25 kWh
Energy for three heaters = 3 × 1.25 = 3.75 kWh
संबंधित प्रश्न
In which direction do electrons flow?
If the amount of electric charge passing through a conductor in 10 minutes is 300 C, the current flowing is:
(a) 30 A
(b) 0.3 A
(c) 0.5 A
(d) 5 A
A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 0.12 Ω. How much current would flow through the 12 Ω resistor?
In the circuit shown below, the voltmeter reads 10 V.
(a) What is the combined resistance?
(b) What current flows?
(c) What is the p.d. across 2 Ω resistor?
(d) What is the p.d. across 3 Ω resistor?
If the lamps are both the same in the figure given below and if A1 reads 0.50 A, what do A2, A3, A4 and A5 read?
Ten bulbs are connected in a series circuit to a power supply line. Ten identical bulbs are connected in a parallel circuit to an identical power supply line.
(a) Which circuit would have the highest voltage across each bulb?
Distinguish between an open and a closed circuit.
An electric bulb is marked '100 W, 250 V'. What information does this convey?
A bulb marked 12 V, 24 W operates on a 12 V battery for 20 minutes. Calculate:
- The current flowing through it, and
- The energy consumed.
