Advertisements
Advertisements
Question
The sum of three consecutive multiples of 7 is 357. Find the smallest multiple.
Options
112
126
119
116
Advertisements
Solution
112
Explanation:
Let the three consecutive multiples of 7 be 7x, (7x + 7), (7x + 14) where x is a natural number.
According to the question,
7x + (7x + 7) + (7x + 14) = 357
⇒ 21x + 21 = 357
⇒ 21(x + 1) = 357
⇒ `(21(x + 1))/21 = 357/21` ...[Dividing both sides by 21]
⇒ x + 1 = 17
⇒ x = 17 – 1 ...[Transposing 1 to RHS]
⇒ x = 16
Hence, the smallest multiple of 7 is 7 × 16, i.e. 112.
APPEARS IN
RELATED QUESTIONS
Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?
The number of boys and girls in a class are in the ratio 7:5. The number of boys is 8 more than the number of girls. What is the total class strength?
The perimeter of a rectangle is 13 cm and its width is `2 3/4` cm. Find its length.
Three consecutive numbers whose sum is 12 are ______, ______ and ______.
The sum of two consecutive multiples of 10 is 210. The smaller multiple is ______.
Shikha’s present age is p years. Reemu’s present age is 4 times the present age of Shikha. After 5 years Reemu’s age will be 15p years.
Two equal sides of a triangle are each 4 m less than three times the third side. Find the dimensions of the triangle, if its perimeter is 55 m.
Anima left one-half of her property to her daughter, one-third to her son and donated the rest to an educational institute. If the donation was worth Rs. 1,00,000, how much money did Anima have?
Hamid has three boxes of different fruits. Box A weighs `2 1/2` kg more than Box B and Box C weighs `10 1/4` kg more than Box B. The total weight of the three boxes is `48 3/4` kg. How many kilograms (kg) does Box A weigh?
An employee works in a company on a contract of 30 days on the condition that he will receive Rs. 120 for each day he works and he will be fined Rs. 10 for each day he is absent. If he receives Rs. 2300 in all, for how many days did he remain absent?
