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Question
Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?
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Solution
Let Baichung’s father’s age be x years. Therefore, Baichung’s age and Baichung’s grandfather’s age will be (x − 29) years and (x + 26) years respectively.
According to the given question, the sum of the ages of these 3 people is 135 years.
∴ x + x − 29 + x + 26 = 135
3x − 3 = 135
On transposing 3 to R.H.S, we obtain
3x = 135 + 3
3x = 138
On dividing both sides by 3, we obtain
`(3x)/3 = 138/3`
x = 46
Baichung’s father’s age = x years = 46 years
Baichung’s age = (x − 29) years = (46 − 29) years = 17 years
Baichung’s grandfather’s age = (x + 26) years = (46 + 26) years = 72 years
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