Advertisements
Advertisements
Question
On dividing Rs. 200 between A and B such that twice of A’s share is less than 3 times B’s share by 200, B’s share is?
Advertisements
Solution
Let B’s share be ₹ x.
Then, A’s share = ₹ (200 – x)
According to the question,
2 × (A’s share) = 3 × (B’s share) – 200
⇒ 2 × (200 – x) = 3x – 200
⇒ 400 – 2x = 3x – 200
⇒ –2x – 3x = –200 – 400
⇒ – 5x = – 600
⇒ x = `-600 xx (- 1/5)`
∴ x = 120
Hence, B’s share is ₹ 120.
APPEARS IN
RELATED QUESTIONS
Three consecutive integers add up to 51. What are these integers?
The perimeter of a rectangle is 13 cm and its width is `2 3/4` cm. Find its length.
Bansi has 3 times as many two-rupee coins as he has five-rupee coins. If he has in all a sum of Rs. 77, how many coins of each denomination does he have?
The sum of two consecutive multiples of 10 is 210. The smaller multiple is ______.
Shikha’s present age is p years. Reemu’s present age is 4 times the present age of Shikha. After 5 years Reemu’s age will be 15p years.
The sum of three consecutive odd natural numbers is 69. Find the prime number out of these numbers.
The sum of three consecutive numbers is 156. Find the number which is a multiple of 13 out of these numbers.
The sum of four consecutive integers is 266. What are the integers?
Hamid has three boxes of different fruits. Box A weighs `2 1/2` kg more than Box B and Box C weighs `10 1/4` kg more than Box B. The total weight of the three boxes is `48 3/4` kg. How many kilograms (kg) does Box A weigh?
The perimeter of a rectangle is 240 cm. If its length is increased by 10% and its breadth is decreased by 20%, we get the same perimeter. Find the length and breadth of the rectangle.
