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Hamid has three boxes of different fruits. Box A weighs 212 kg more than Box B and Box C weighs 1014 kg more than Box B. The total weight of the three boxes is 4834 kg

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Question

Hamid has three boxes of different fruits. Box A weighs `2 1/2` kg more than Box B and Box C weighs `10 1/4` kg more than Box B. The total weight of the three boxes is `48 3/4` kg. How many kilograms (kg) does Box A weigh?

Sum
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Solution

Let the weight of box A be x kg.

According to the question,

Weight of Box A = Weight of Box B + `5/2` kg  ...[Given]

⇒ Weight of box B = `(x - 5/2)` kg

And weight of Box C = Weight of box B + `41/4` kg  ...[Given]

⇒ Weight of Box C = `x - 5/2 + 41/4` kg

= `x + ((-10 + 41)/4)` kg

= `(x + 31/4)` kg

As, total weight of three boxes = `48 3/4` kg = `195/4` kg    ...[Given]

∵ Total weight of three boxes = Weight of box A + Weight of box B + Weight of box C

∴ `195/4 = x + x - 5/2 + x + 31/4`

⇒ `195/4 = 3x + (31 - 10)/4`

⇒ `195/4 = 3x + 21/4`

⇒ `3x = 195/4 - 21/4`

⇒ `3x = (195 - 21)/4`

⇒ `3x = 174/4`

⇒ `x = 174/(3 xx 4)`

⇒ `x = 29/2`

∴ `x = 14 1/2` kg

Hence, box A weight `14 1/2` kg.

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Chapter 4: Linear Equation In One Variable - Exercise [Page 119]

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NCERT Exemplar Mathematics Exemplar [English] Class 8
Chapter 4 Linear Equation In One Variable
Exercise | Q 95. | Page 119

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