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Question
The principal value of sin–1 `(- sqrt3/2)` is ______.
Options
`(- (2pi)/3)`
`(4pi)/3`
`(5pi)/3`
`- pi/3`
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Solution
The principal value of sin–1 `(- sqrt3/2)` is `underlinebb(-pi/3)`.
Explanation:
`sin^-1(-sqrt3/2) = [sin^-1 sin(- pi/3)] = -pi/3`
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