English

Select the correct option from the given alternatives: If cos p θ = cos q θ, p ≠ q, then,

Advertisements
Advertisements

Question

Select the correct option from the given alternatives:

If cos pθ = cos qθ, p ≠ q, then ______.

Options

  • θ = `(2npi)/(p +- q)`

  • θ = 2nπ

  • θ = 2nπ ± p

  • θ = 2nπ ± q

MCQ
Fill in the Blanks
Advertisements

Solution

If cos pθ = cos qθ, p ≠ q, then, θ = `bb(underline((2npi)/(p +- q))`

Explanation:

Given, cos pθ = cos qθ

cos pθ – cos qθ = 0

`2sin((pθ + qθ)/2) sin((pθ - qθ)/2)` = 0  ...(cos C – cos D)

`sin((pθ + qθ)/2)` = 0 or `sin  ((pθ - qθ)/2)` = 0

`(pθ + qθ)/2` = nπ or `(pθ - qθ)/2` = nπ

θ = `(2nπ)/((p + q))` or `(2nπ)/((p - q))` = θ

∴ θ = `(2nπ)/(p +- q)`

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Trigonometric Functions - Miscellaneous exercise 3 [Page 106]

RELATED QUESTIONS

Find the principal solution of the following equation: 

Sec θ = `(2)/sqrt(3)`


Find the principal solution of the following equation:

cot θ = 0


Find the principal solution of the following equation:

sin θ = `-1/2`


Find the general solution of the following equation:

tan θ = - 1


Find the general solution of the following equation:

sin θ = tan θ


With the usual notations prove that `2{asin^2  "C"/(2) + "c"sin^2  "A"/(2)}` = a – b + c.


Select the correct option from the given alternatives:

If polar coordinates of a point are `(2, pi/4)`, then its cartesian coordinates are


If `sqrt3`cos x - sin x = 1, then general value of x is ______.


Select the correct option from the given alternatives:

In ΔABC, ac cos B - bc cos A = _______


If in a triangle, the angles are in A.P. and b: c = `sqrt3: sqrt2`, then A is equal to


Select the correct option from the given alternatives:

The value of cot (tan-12x + cot-12x) is


The principal value of sin1 `(- sqrt3/2)` is ______.


If tan θ + tan 2θ + tan 3θ = tan θ.tan 2θ. tan 3θ, then the general value of the θ is ______.


Select the correct option from the given alternatives:

In any ΔABC, if acos B = bcos A, then the triangle is


Find the principal solutions of the following equation:

tan 3θ = - 1


Find the general solutions of the following equation:

`tan theta = - sqrt3`


Find the general solutions of the following equation:

`tan^2 theta = 3`


With the usual notations, prove that `(sin("A" - "B"))/(sin ("A" + "B")) = ("a"^2 - "b"^2)/"c"^2`


If sin-1(1 - x) - 2 sin-1x =  `pi/2`, then find the value of x.


Show that `tan^-1  1/2 - tan^-1  1/4 = tan^-1  2/9`.


Show that `cos^-1  sqrt3/2 + 2 sin^-1  sqrt3/2 = (5pi)/6`.


If x, y, z are positive, then prove that

`tan^-1 (("x - y")/(1 + "xy")) + tan^-1 (("y - z")/(1 + "yz")) + tan^-1 (("z - x")/(1 + "zx")) = 0`


The principal solutions of `sqrt(3)` sec x − 2 = 0 are ______


Find the principal solutions of sin x = `-1/2`


If cos–1x + cos–1y – cos–1z = 0, then show that x2 + y2 + z2 – 2xyz = 1


The value of tan 57°- tan 12°- tan 57° tan 12° is ______.


`int (sin (log x))^2/x` log x dx = ?


`[sin (tan^-1  3/4)]^2 + [sin(tan^-1  4/3)]^2 = ?`


If x + y = `pi/2`, then the maximum value of sin x. sin y is.


The principal solutions of cot x = `sqrt3` are ______.


The values of x in `(0, pi/2)` satisfying the equation sin x cos x = `1/4` are ______.


The number of solutions of `sin^2 theta = 1/2` in [0, π] is ______.


The number of solutions of cos 2θ = sin θ in (0, 2π) is ______


The general solution of the equation tan θ tan 2θ = 1 is given by ______ 


The general value of θ in the equation `2sqrt(3) cos theta = tan theta` is ______.


The equation 3sin2x + 10 cos x – 6 = 0 is satisfied, if ______.


The number of solutions of sin x + sin 3x + sin 5x = 0 in the interval `[pi/2, (3pi)/2]` is ______.


The general solution of the equation tan θ + tan 4θ + tan 7θ = tan θ tan 4θ tan 7θ is ______.


Principal solutions at the equation sin 2x + cos 2x = 0, where π < x < 2 π are ______.


The general solution to cos100x – sin100x = 1 is ______.


The general solution of cot 4x = –1 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×