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Select the correct option from the given alternatives: If cos p θ = cos q θ, p ≠ q, then,

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प्रश्न

Select the correct option from the given alternatives:

If cos pθ = cos qθ, p ≠ q, then ______.

विकल्प

  • θ = `(2npi)/(p +- q)`

  • θ = 2nπ

  • θ = 2nπ ± p

  • θ = 2nπ ± q

MCQ
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उत्तर

If cos pθ = cos qθ, p ≠ q, then, θ = `bb(underline((2npi)/(p +- q))`

Explanation:

Given, cos pθ = cos qθ

cos pθ – cos qθ = 0

`2sin((pθ + qθ)/2) sin((pθ - qθ)/2)` = 0  ...(cos C – cos D)

`sin((pθ + qθ)/2)` = 0 or `sin  ((pθ - qθ)/2)` = 0

`(pθ + qθ)/2` = nπ or `(pθ - qθ)/2` = nπ

θ = `(2nπ)/((p + q))` or `(2nπ)/((p - q))` = θ

∴ θ = `(2nπ)/(p +- q)`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १०६]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 1.04 | पृष्ठ १०६

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