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Find the principal solution of the following equation: 3 cosecθ + 2 = 0 - Mathematics and Statistics

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प्रश्न

Find the principal solution of the following equation:

`sqrt(3)` cosecθ + 2 = 0 

योग
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उत्तर

`sqrt(3)` cosec θ + 2 = 0 

`sqrt(3)` cosec θ = - 2 

cosec θ = `(-2)/sqrt(3)`

sin θ =  `-sqrt(3)/(2)`

sin θ = `-sin(pi/3)`

sin θ = `sin(pi + pi/3)` and sin θ = `sin (2pi - pi/3)`

sin θ = `sin ((4pi)/3)` and sin θ  = `sin ((5pi)/3)`

= `[therefore 0≤ (4pi)/3 < 2pi and 0≤ (5pi)/3< 2pi]`

θ = `(4pi)/(3)` and θ = `(5pi)/(3)`

Principal solutions one  `(4pi)/(3)` and  `(5pi)/(3)`.

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Trigonometric Equations and Their Solutions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Exercise 3.1 | Q 2.3 | पृष्ठ ७५

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