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Find the general solution of the following equation: tan θ2θ3=3

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प्रश्न

Find the general solution of the following equation:

tan `(2θ)/(3) = sqrt3`

योग
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उत्तर

The general solution of tan θ = tan α is

θ = nπ + α, n ∈ Z

Now, 

tan `(2θ)/(3) = sqrt3`.

∴ tan `(2θ)/(3) = tan  pi/(3)           ...[∵ tan  pi/(3) = sqrt(3)]`

∴ The required general solution is given by

`(2θ)/(3) =  nπ +  pi/(3)`, n ∈ Z

i.e. θ = `(3npi)/(2) + pi/(2)`, n ∈ Z

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अध्याय 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Exercise 3.1 | Q 5.2 | पृष्ठ ७५

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