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Find the general solution of the following equation: sec θ = 2.

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प्रश्न

Find the general solution of the following equation:

sec θ = `sqrt(2)`.

योग
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उत्तर

The general solution of cos θ = cos α is
θ = 2nπ ± α, n ∈ Z.
Now,
sec θ  = √2                   

∴ cos θ = `(1)/sqrt(2)`

∴ cos θ = cos  `pi/(4)    ...[∵ cos  pi/(4) = (1)/sqrt(2)]`
∴ the required general solution is
θ = 2nπ ±  `pi/(4)`, n ∈ Z.

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अध्याय 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Exercise 3.1 | Q 4.1 | पृष्ठ ७५

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