हिंदी

If x, y, z are positive, then prove that x - yxyy - zyzz - xzxtan-1(x - y1+xy)+tan-1(y - z1+yz)+tan-1(z - x1+zx)=0 - Mathematics and Statistics

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प्रश्न

If x, y, z are positive, then prove that

`tan^-1 (("x - y")/(1 + "xy")) + tan^-1 (("y - z")/(1 + "yz")) + tan^-1 (("z - x")/(1 + "zx")) = 0`

योग
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उत्तर

LHS = `tan^-1 (("x - y")/(1 + "xy")) + tan^-1 (("y - z")/(1 + "yz")) + tan^-1 (("z - x")/(1 + "zx"))`

`= tan^-1 "x" - tan^-1"y" + tan^-1"y" - tan^-1"z" + tan^-1"z" - tan^-1"x"`     .......[∵ x > 0, y > 0, z > 0]

= 0

= RHS

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Trigonometric Equations and Their Solutions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १११]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 37 | पृष्ठ १११

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