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If tan-12x + tan-13x = π4, then find the value of x. - Mathematics and Statistics

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प्रश्न

If tan-12x + tan-13x = `pi/4`, then find the value of x.

योग
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उत्तर

tan-12x + tan-13x = `pi/4`

∴ `tan^-1  ((2"x" + 3"x")/(1 - "2x" xx "3x")) = pi/4`, where 2x > 0, 3x > 0

∴ `"5x"/(1 - "6x"^2) = tan  pi/4 = 1`

∴ 5x = 1 - 6x2

∴ 6x2 + 5x - 1 = 0

∴ 6x2 + 6x - x - 1 = 0

∴ 6x(x + 1) - 1(x + 1) = 0

∴ (x + 1)(6x - 1) = 0

∴ x = -1 or x = `1/6`

But x > 0  ∴ x ≠ - 1

Hence, x = `1/6`

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Trigonometric Equations and Their Solutions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ ११०]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 29 | पृष्ठ ११०

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