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Find the principal solution of the following equation: sin θ = -12

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प्रश्न

Find the principal solution of the following equation:

sin θ = `-1/2`

योग
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उत्तर

We now that,
`sin  (pi)/(6) = (1)/(2) and sin(pi + θ)` = – sin θ,
sin(2π - θ) = – sinθ.

∴ `sin(pi + pi/6) = -sin pi/(6) = -(1)/(2)`

`"and" sin(2pi - pi/6) = - sin  pi/6 = - (1)/(2)`

∴ `sin  (7pi)/(6) = sin  (11pi)/(6) = -(1)/(2)`, where

`0 < (7pi)/(6) < 2pi and 0 < (11pi)/(6) < 2pi`

∴ sinθ = `-(1)/(2)"gives"`,

sinθ = `sin  (7pi)/(6) = sin  (11pi)/(6)`

∴ θ = `(7pi)/(6) and θ = (11pi)/(6)`
Hence, the required principal solutions are

θ = `(7pi)/(6) and θ = (11pi)/(6)`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Exercise 3.1 | Q 2.1 | पृष्ठ ७५

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