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Prove the following: xxxcos-1x=tan-1(1-x2x), if x > 0

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प्रश्न

Prove the following:

`cos^-1 "x" = tan^-1 (sqrt(1 - "x"^2)/"x")`, if x > 0

योग
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उत्तर

Let cos-1 x = α

Then, cos α = x, where 0 < α < π

Since, x > 0, 0 < α < `pi/2`

∴ sin α > 0, cos α > 0

Now, `tan^-1 (sqrt(1 - "x"^2)/"x") = tan^-1  (sqrt(1 - cos^2 alpha)/cos alpha)`

`= tan^-1  (sqrt(sin^2 alpha)/cos alpha)`

`= tan^-1  (tan  alpha)`

`= alpha = cos^-1 "x"`

Hence, `cos^-1 "x" = tan^-1 (sqrt(1 - "x"^2)/"x")`, if x > 0

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अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १११]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 35.1 | पृष्ठ १११

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