हिंदी

Select the correct option from the given alternatives: tantan2tan-1(13)+tan-1(17)=_____

Advertisements
Advertisements

प्रश्न

Select the correct option from the given alternatives:

`2 "tan"^-1 (1/3) + "tan"^-1 (1/7) =` _____

विकल्प

  • `"tan"^-1(4/5)`

  • `pi/2`

  • 1

  • `pi/4`

MCQ
Advertisements

उत्तर

`2 "tan"^-1 (1/3) + "tan"^-1 (1/7) = pi/4`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १०८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 1.15 | पृष्ठ १०८

संबंधित प्रश्न

Find the principal solution of the following equation: 

cosθ = `(1)/(2)`


Find the principal solution of the following equation: 

Sec θ = `(2)/sqrt(3)`


Find the general solution of the following equation :

cosθ = `sqrt(3)/(2)`


Find the general solution of the following equation:

cot θ = 0.


Find the general solution of the following equation:

sec θ = `sqrt(2)`.


Find the general solution of the following equation:

sin 2θ = `1/2`


Find the general solution of the following equation:

cos 4θ = cos 2θ


Find the general solution of the following equation: 

tan3θ = 3 tanθ.


Find the general solution of the following equation:

cosθ + sinθ = 1.


State whether the following equation has a solution or not?

cos2θ = – 1.


State whether the following equation has a solution or not?

2sinθ = 3


In ΔABC, if ∠A = 45°, ∠B = 60° then find the ratio of its sides.


Select the correct option from the given alternatives:

The principal solutions of equation cot θ = `sqrt3` are ______.


Select the correct option from the given alternatives:

In ΔABC, ac cos B - bc cos A = _______


Select the correct option from the given alternatives:

The value of cot (tan-12x + cot-12x) is


The principal value of sin–1 `(- sqrt3/2)` is ______.


If `"sin"^-1 4/5 + "cos"^-1 12/13 = "sin"^-1 alpha`, then α = ______.


Select the correct option from the given alternatives:

`"tan"(2"tan"^-1 (1/5) - pi/4)` = ______


`cos[tan^-1  1/3 + tan^-1  1/2]` = ______


Select the correct option from the given alternatives:

In any ΔABC, if acos B = bcos A, then the triangle is


Find the principal solutions of the following equation:

cot θ = 0


Find the general solutions of the following equation:

sin θ - cos θ = 1


With the usual notations, prove that `(sin("A" - "B"))/(sin ("A" + "B")) = ("a"^2 - "b"^2)/"c"^2`


In Δ ABC, if cos A = sin B - cos C then show that it is a right-angled triangle.


State whether the following equation has a solution or not?

3 sin θ = 5


If 2 tan-1(cos x) = tan-1(2 cosec x), then find the value of x.


If tan-12x + tan-13x = `pi/4`, then find the value of x.


Show that `2 cot^(-1)  3/2 +  sec^(-1)  13/12 = π/2`


If `tan^-1 "x" + tan^-1 "y" + tan^-1 "z" = pi/2,` then show that xy + yz + zx = 1


Find the principal solutions of cos 2𝑥 = 1


`cos^-1 (cos  (4pi)/3)` = ______.


The value of tan 57°- tan 12°- tan 57° tan 12° is ______.


`int 1/(sin x * cos x)` dx = ?


If f(x) = sin-1`(sqrt((1 - x)/2))`, then f'(x) = ?


The principal solutions of cot x = `sqrt3` are ______.


If 2 cos2 θ + 3 cos θ = 2, then permissible value of cos θ is ________.


If function

f(x) = `x - |x|/x, x < 0`
      = `x + |x|/x, x > 0`
      = 1, x = 0, then


The value of θ in (π, 2π) satisfying the equation sin2θ - cos2θ = 1 is ______ 


The general solution of the equation tan θ tan 2θ = 1 is given by ______ 


The general solution of x(1 + y2)1/2 dx + y(1 + x2)1/2 dy = 0 is ______.


General solution of the equation sin 2x – sin 4x + sin 6x = 0 is ______.


Principal solutions at the equation sin 2x + cos 2x = 0, where π < x < 2 π are ______.


If a = sin θ + cos θ, b = sin3 θ + cos3 θ, then ______.


Find the general solution of sin θ + sin 3θ + sin 5θ = 0


Prove that the general solution of cos θ = cos α is θ = 2nπ ± α, n ∈ Z.


The general solution of cot 4x = –1 is ______.


If tan3θ = cotθ, then θ =


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×