हिंदी

If tan θ + tan 2θ + tan 3θ = tan θ.tan 2θ. tan 3θ, then the general value of the θ is ______.

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प्रश्न

If tan θ + tan 2θ + tan 3θ = tan θ.tan 2θ. tan 3θ, then the general value of the θ is ______.

विकल्प

  • `("n"pi)/6`

  • `"n"pi +- pi/4`

  • `("n"pi)/2`

MCQ
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उत्तर

If tan θ + tan 2θ + tan 3θ = tan θ.tan 2θ. tan 3θ, then the general value of the θ is `("n"pi)/6`.

Explanation:

tan (A + B + C) = `(tan A + tan B - tanA. tan B. tan C)/(1 - tan A.tan B - tan B.tanC - tan C.tan A)`

Since, tan θ + tan 2θ + tan 3θ = tan θ.tan

2θ.tan 3θ,

we get, tan (θ + 2θ + 3θ) =  θ

∴ tan 6θ = 0

∴ 6θ = nπ

 θ = `(npi)/6`

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अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १०८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 1.19 | पृष्ठ १०८

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