English

Find the principal solution of the following equation: 3 cosecθ + 2 = 0

Advertisements
Advertisements

Question

Find the principal solution of the following equation:

`sqrt(3)` cosecθ + 2 = 0 

Sum
Advertisements

Solution

`sqrt(3)` cosec θ + 2 = 0 

`sqrt(3)` cosec θ = - 2 

cosec θ = `(-2)/sqrt(3)`

sin θ =  `-sqrt(3)/(2)`

sin θ = `-sin(pi/3)`

sin θ = `sin(pi + pi/3)` and sin θ = `sin (2pi - pi/3)`

sin θ = `sin ((4pi)/3)` and sin θ  = `sin ((5pi)/3)`

= `[therefore 0≤ (4pi)/3 < 2pi and 0≤ (5pi)/3< 2pi]`

θ = `(4pi)/(3)` and θ = `(5pi)/(3)`

Principal solutions one  `(4pi)/(3)` and  `(5pi)/(3)`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Trigonometric Functions - Exercise 3.1 [Page 75]

APPEARS IN

RELATED QUESTIONS

Find the principal solution of the following equation: 

cosθ = `(1)/(2)`


Find the principal solution of the following equation:

sin θ = `-1/2`


Find the general solution of the following equation :

cosθ = `sqrt(3)/(2)`


Find the general solution of the following equation:

cosec θ = - √2.


Find the general solution of the following equation:

4sin2θ = 1.


Find the general solution of the following equation:

sin θ = tan θ


State whether the following equation have solution or not?

3 tanθ = 5


With usual notations prove that 2(bc cosA + ac cosB + ab cosC) = a2 + b2 + c2 .


Select the correct option from the given alternatives:

The principal solutions of equation sin θ = `- 1/2` are ______.


Select the correct option from the given alternatives:

If polar coordinates of a point are `(2, pi/4)`, then its cartesian coordinates are


Select the correct option from the given alternatives:

In Δ ABC if ∠A = 45°, ∠B = 30°, then the ratio of its sides are


Select the correct option from the given alternatives:

In ΔABC if c2 + a2 – b2 = ac, then ∠B = ____.


If in a triangle, the angles are in A.P. and b: c = `sqrt3: sqrt2`, then A is equal to


`"cos"^-1 ("cos" (7pi)/6)` = _________.


Select the correct option from the given alternatives:

The value of cot (tan-12x + cot-12x) is


The principal value of sin–1 `(- sqrt3/2)` is ______.


Select the correct option from the given alternatives:

If tan-1(2x) + tan-1(3x) = `pi/4`, then x = _____


Select the correct option from the given alternatives:

`2 "tan"^-1 (1/3) + "tan"^-1 (1/7) =` _____


`cos[tan^-1  1/3 + tan^-1  1/2]` = ______


Find the general solutions of the following equation:

`tan^2 theta = 3`


With the usual notations, prove that `(sin("A" - "B"))/(sin ("A" + "B")) = ("a"^2 - "b"^2)/"c"^2`


Show that `cot^-1  1/3 - tan^-1  1/3 = cot^-1  3/4`.


Show that `tan^-1  1/2 = 1/3  tan^-1  11/2`


Prove the following:

`cos^-1 "x" = tan^-1 (sqrt(1 - "x"^2)/"x")`, if x > 0


Prove the following:

`cos^-1 "x" = pi + tan^-1 (sqrt(1 - "x"^2)/"x")`, if x < 0


If x, y, z are positive, then prove that

`tan^-1 (("x - y")/(1 + "xy")) + tan^-1 (("y - z")/(1 + "yz")) + tan^-1 (("z - x")/(1 + "zx")) = 0`


If `tan^-1 "x" + tan^-1 "y" + tan^-1 "z" = pi/2,` then show that xy + yz + zx = 1


Find the principal solutions of sin x = `-1/2`


If cos–1x + cos–1y – cos–1z = 0, then show that x2 + y2 + z2 – 2xyz = 1


`cos^-1 (cos  (4pi)/3)` = ______.


The value of tan 57°- tan 12°- tan 57° tan 12° is ______.


`int 1/(sin x * cos x)` dx = ?


If f(x) = sin-1`(sqrt((1 - x)/2))`, then f'(x) = ?


If y = sin-1 `[(sqrt(1 + x) + sqrt(1 - x))/2]`, then `"dy"/"dx"` = ?


The number of solutions of `sin^2 theta = 1/2` in [0, π] is ______.


If function

f(x) = `x - |x|/x, x < 0`
      = `x + |x|/x, x > 0`
      = 1, x = 0, then


If 4 sin-1x + 6 cos-1 x = 3π then x = ______.


The general value of θ in the equation `2sqrt(3) cos theta = tan theta` is ______.


Find the principal solutions of cot θ = 0


If 2 tan–1(cos x) = tan–1(2 cosec x). then find the value of x.


Which of the following equation has no solution?


Principal solutions at the equation sin 2x + cos 2x = 0, where π < x < 2 π are ______.


Prove that the general solution of cos θ = cos α is θ = 2nπ ± α, n ∈ Z.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×