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In Δ ABC, prove that cos(A-B2)=(a+bc)sin C2 . - Mathematics and Statistics

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Question

In Δ ABC, prove that `cos(("A" - "B")/2) = (("a" + "b")/"c")sin  "C"/2` .

Sum
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Solution

By the sine rule,

`"a"/(sin "A") = "b"/(sin "B") = "c"/(sin "C") = "k"`

∴ a = k sin A, b = k sin B, c = k sin C

RHS = `(("a" + "b")/"c") sin  "C"/2`

`= (("k sin A" + "k sin B")/("k sin C")) sin  "C"/2`

`= (("sin A" + "sin B")/"sin C") sin  "C"/2`

`= (2sin (("A" + "B")/2). cos  ("A" - "B")/2)/(2"sin"  "C"/2. cos  "C"/2). sin  "C"/2`

 `= ("sin" ("A" + "B")/2. cos  ("A" - "B")/2)/(cos  "C"/2)`

`= (sin (pi/2 - "C"/2).cos  ("A" - "B")/2)/(cos  "C"/2)   ...[because "A" + "B" + "C" = pi]`

`= (cos  "C"/2.cos  ("A" - "B")/2)/(cos  "C"/2)`

`= cos  (("A" - "B")/2)`

= LHS

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Chapter 3: Trigonometric Functions - Miscellaneous exercise 3 [Page 109]

APPEARS IN

Balbharati Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 5 | Page 109

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