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Question
The most commonly used reducing agent is ______.
Options
AlCl3
PbCl2
SnCl4
SnCl2
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Solution
The most commonly used reducing agent is SnCl2.
Explanation:
+4 oxidation state of Sn is more stable than +2 oxidation state. Therefore, Sn2+ can be easily oxidised to Sn4+ and hence SnCl2 acts a reducing agent.
\[\ce{SnCl2 + 2Cl -> SnCl4 + 2e–}\]
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