English
Karnataka Board PUCPUC Science Class 11

Aluminium dissolves in mineral acids and aqueous alkalies and thus shows amphoteric character. A piece of aluminium foil is treated with dilute hydrochloric acid or dilute sodium hydroxide solutio

Advertisements
Advertisements

Question

Aluminium dissolves in mineral acids and aqueous alkalies and thus shows amphoteric character. A piece of aluminium foil is treated with dilute hydrochloric acid or dilute sodium hydroxide solution in a test tube and on bringing a burning matchstick near the mouth of the test tube, a pop sound indicates the evolution of hydrogen gas. The same activity when performed with concentrated nitric acid, reaction doesn’t proceed. Explain the reason.

Short/Brief Note
Advertisements

Solution

Al being amphoteric dissolves both in acids and alkalies evolving H2 gas which bums with a pop sound.

\[\ce{2Al + 6HCl -> 2AlCl3 + 3H2}\]

\[\ce{2Al + 2NaOH + 2H2O -> \underset{Sod meta-aluminate}{2NaAlO2} + 3H2}\]

With conic. HNO3, Al becomes passive and the reaction does not proceed. This passivity is due to the formation of a thin protective layer of its oxide (Al2O3) on the surface of the metal which prevents further action.

\[\ce{2Al + 6HNO3 -> Al2O3 + 6NO2 + 3H2O}\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 11: The p-block Elements - Multiple Choice Questions (Type - I) [Page 138]

APPEARS IN

NCERT Exemplar Chemistry [English] Class 11
Chapter 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 32 | Page 138

RELATED QUESTIONS

If B–Cl bond has a dipole moment, explain why BCl3 molecule has zero dipole moment.


How would you explain the lower atomic radius of Ga as compared to Al?


Write a balanced equation for Al + NaOH → ?


The geometry of a complex species can be understood from the knowledge of type of hybridisation of orbitals of central atom. The hybridisation of orbitals of central atom in [Be(OH)4] and the geometry of the complex are respectively.


In the structure of diborane ______.


The most commonly used reducing agent is ______.


Cement, the important building material is a mixture of oxides of several elements. Besides calcium, iron and sulphur, oxides of elements of which of the group (s) are present in the mixture?


Explain why the following compounds behave as Lewis acids?

BCl3


Explain the following:

Boron does not exist as B3+ ion.


Explain the following:

PbX2 is more stable than PbX4.


Explain the following:

Pb4+ acts as an oxidising agent but Sn2+ acts as a reducing agent.


Identify the compounds A, X and Z in the following reactions:

\[\ce{A + 2HCl + 5H2O -> 2NaCl + X}\]


Complete the following chemical equations:

\[\ce{Z + 3 LiAlH4 -> X + 3LiF + 3AlF_3}\]

\[\ce{X + 6H2 -> Y + 6H2}\]

\[\ce{3X + 3O2 ->[Δ] B2O3 + 3H2O}\]


Match the species given in Column I with the properties mentioned in Column II.

Column I Column II
(i) \[\ce{BF^{-}4}\] (a) Oxidation state of central atom is +4
(ii) AICI3 (b) Strong oxidising agent
(iii) SnO (c) Lewis acid
(iv) PbO2 (d) Can be further oxidised
  (e) Tetrahedral shape

Match the species given in Column I with the hybridisation given in Column II.

Column I Column II
(i) Boron in [B(OH)4] (a) sp2
(ii) Aluminium in [Al(H2O)6]3+ (b) sp3
(iii) Boron in B2H6 (c) sp3d2
(iv) Carbon in Buckminsterfullerene  
(v) Silicon in \[\ce{SiO^{4-}4}\]  
(vi) Germanium in [GeCl6]2–  

Describe the general trends in the following properties of the elements in Groups 13 and 14.

Ionisation enthalpy


Describe the general trends in the following properties of the elements in Groups 13 and 14.

Nature of halides


Three pairs of compounds are given below. Identify that compound in each of the pairs which has group 13 element in more stable oxidation state. Give reason for your choice. State the nature of bonding also.

TlCl3, TlCl


Boron fluoride exists as BF3 but boron hydride doesn’t exist as BH3. Give reason. In which form does it exist? Explain its structure.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×