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Question
The measure of one angle of a parallelogram is 70°. What are the measures of the remaining angles?
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Solution
\[\text{ Given that one angle of the parallelogram is } 70° . \]
\[\text{ Since opposite angles have same value, if one is }70° , \text{ then the one directly opposite will also be } 70° . \]
\[\text{ So, let one angle be }x° . \]
\[x° + 70° = 180° (\text{ the sum of adjacent angles of a parallelogram is } 180° )\]
\[x° = 180° - 70° \]
\[x° = 110° \]
\[\text{ Thus, the remaining angles are }110° , 110° \text{ and }70° . \]
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