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The first term of an A.P. is 2 and the last term is 50. The sum of all these terms is 442. Find the common difference.

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Question

The first term of an A.P. is 2 and the last term is 50. The sum of all these terms is 442. Find the common difference.

Sum
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Solution

Let the number of terms of the given A.P. be n, first term be a and the common difference be d.

First term a = 2

Last term l = 50

Sum of all the terms Sn = 442

We know that,

Sum of the n terms Sn = `n/2(a + l)`

`=> 442 = n/2 (2 + 50)`

`=> 442 = n(26)`

`=> n = 442/26`

⇒ n = 17

Also,

l = a + (n - 1)d

Therefore,

On substituting the values of a, l and n, we get,

50 = 2 + (17 - 1)d

⇒ 50 = 2 + 16d

⇒ 50 - 2 = 16d

⇒ 48 = 16d

⇒ `48/16` = d

⇒ d = 3

Hence, the common difference of the given A.P. is 3.

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Chapter 19: Arithmetic Progression - Exercise 19.4 [Page 31]

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R.D. Sharma Mathematics [English] Class 11
Chapter 19 Arithmetic Progression
Exercise 19.4 | Q 19 | Page 31

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