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Question
A man starts repaying a loan as first instalment of Rs 100 = 00. If he increases the instalments by Rs 5 every month, what amount he will pay in the 30th instalment?
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Solution
Let
\[a_{30}\] be the amount a man repays in the 30th instalment.
Let d be the common increment in his instalment every month.
Let a be the initial repayment.
Here, a = 100, d = 5, n = 30
Amount to be repaid in the 30th instalment:
\[a_{30}\]
\[\Rightarrow\] a+ \[\left( n - 1 \right)\] d
\[= 100 + 29 \times 5\]
\[ = 245\]
Hence, the man repays Rs 245 in his 30th instalment.
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