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The Fibonacci Sequence is Defined by A1 = 1 = A2, an = an − 1 + an − 2 for N > 2 Find a N + 1 a N for N = 1, 2, 3, 4, 5.

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Question

The Fibonacci sequence is defined by a1 = 1 = a2, an = an − 1 + an − 2 for n > 2

Find `(""^an +1)/(""^an")` for n = 1, 2, 3, 4, 5.

 

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Solution

a1 = 1 = a2, an = an − 1 + an − 2 for n > 2
Then, we have:

\[a_3 = a_2 + a_1 = 1 + 1 = 2\]

\[ a_4 = a_3 + a_2 = 2 + 1 = 3\]

\[ a_5 = a_4 + a_3 = 3 + 2 = 5\]

\[ a_6 = a_5 + a_4 = 5 + 3 = 8\]

\[\text { For } n = 1, \frac{a_{n + 1}}{a_n} = \frac{a_2}{a_1} = \frac{1}{1} = 1\]

\[\text { For }n = 2, \frac{a_{n + 1}}{a_n} = \frac{a_3}{a_2} = \frac{2}{1} = 2\]

\[\text{For } n = 3, \frac{a_{n + 1}}{a_n} = \frac{a_4}{a_3} = \frac{3}{2}\]

\[\text { For } n = 4, \frac{a_{n + 1}}{a_n} = \frac{a_5}{a_4} = \frac{5}{3}\]

\[\text { For } n = 5, \frac{a_{n + 1}}{a_n} = \frac{a_6}{a_5} = \frac{8}{5}\]

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