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The equation for the burning of octane is: 2CA6HA18+25OA2⟶16COA2+18HA2O If the relative molecular mass of carbon dioxide is 44, what is the mass of carbon dioxide produced by burning two moles of

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Question

The equation for the burning of octane is:

\[\ce{2C6H18 + 25O2 -> 16CO2 + 18H2O}\]

If the relative molecular mass of carbon dioxide is 44, what is the mass of carbon dioxide produced by burning two moles of octane?

Numerical
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Solution

1 mole of carbon dioxide has molecular mass = 44

16 moles of carbon dioxide has molecular mass = 44 × 16

= 704 g

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Chapter 5: Mole Concept and Stoichiometry - Exercise 8 [Page 122]

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Frank Chemistry Part 2 [English] Class 10 ICSE
Chapter 5 Mole Concept and Stoichiometry
Exercise 8 | Q 3.3 | Page 122
S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
MISCELLANEOUS EXERCISE | Q 13. (iii) | Page 96
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