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The equation for the burning of octane is: 2CA8HA18+25OA2⟶16COA2+18HA2O What is the empirical formula of octane?

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Question

The equation for the burning of octane is:

\[\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}\]

What is the empirical formula of octane?

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Solution

Empirical formula of octane is C4H9.

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Chapter 5: Mole Concept and Stoichiometry - Exercise 8 [Page 122]

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Frank Chemistry Part 2 [English] Class 10 ICSE
Chapter 5 Mole Concept and Stoichiometry
Exercise 8 | Q 3.5 | Page 122
S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
MISCELLANEOUS EXERCISE | Q 13. (iv) | Page 96

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