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Question
10.47 g of a compound contained 6.25 g of metal A and rest non-metal B. Calculate the empirical formula of the compound [At. wt of A = 207, B = 35.5]
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Solution
Given: Weight of the compound: 10.47g
Weight of metal A = 6.25g
Weight of non-metal B = 10.47 – 6.25 = 4.22g
|
Element |
mass |
At. Wt. |
Relative no. of atoms |
Simplest ratio |
|
A |
6.25 |
207 |
`6.25/207` = 0.03 |
`0.03/0.03` = 1 |
|
B |
4.22 |
35.5 |
`4.26/35.5` = 0.12 |
`0.12/0.03` = 4 |
Hence, the empirical formula is AB4
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