हिंदी

The equation for the burning of octane is: 2CA6HA18+25OA2⟶16COA2+18HA2O If the relative molecular mass of carbon dioxide is 44, what is the mass of carbon dioxide produced by burning two moles of

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प्रश्न

The equation for the burning of octane is:

\[\ce{2C6H18 + 25O2 -> 16CO2 + 18H2O}\]

If the relative molecular mass of carbon dioxide is 44, what is the mass of carbon dioxide produced by burning two moles of octane?

संख्यात्मक
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उत्तर

1 mole of carbon dioxide has molecular mass = 44

16 moles of carbon dioxide has molecular mass = 44 × 16

= 704 g

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अध्याय 5: Mole concept and Stoichiometry - MISCELLANEOUS EXERCISE [पृष्ठ ९६]

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एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
MISCELLANEOUS EXERCISE | Q 13. (iii) | पृष्ठ ९६

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