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Potassium Nitrate on Strong Heating Decomposes as Under : 2kn03 --> 2kn02 + 0 2 Calculate : Weight of Potassium Nitrite Formed . - Chemistry

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प्रश्न

Potassium nitrate on strong heating decomposes as under :
2KNO3 → 2KNO2 + O2
Calculate : Weight of potassium nitrite formed.
(K = 39, 0 = 16, N = 14)

योग
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उत्तर

From the equation :
Molecular weight of KNO3 = (Atomic mass of K + Atomic mass of N + Atomic mass of O) = (39 + 14 + 16 x 3 ) = 101
Molecular mass of of KNO2 = (39 + 14 + 16 x 2) = 85
From the reaction :
2 moles of KNO3 gives = 2 moles of KNO2
So, 202g of KNO3 gives = 170g of KNO2

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अध्याय 5: Mole Concept And Stoichiometry - Exercise 2 [पृष्ठ ११६]

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फ्रैंक Chemistry Part 2 [English] Class 10 ICSE
अध्याय 5 Mole Concept And Stoichiometry
Exercise 2 | Q 8.1 | पृष्ठ ११६

संबंधित प्रश्न

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2KNO3 → 2KNO2 + O2
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