हिंदी

Calculate the Percentage of Phosphorous in the Fertilizer Superphosphate, Ca(H2po4)2. Ca = 40, H =1, P =31, O = 16 (Correct to 1 Decimal Place)

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प्रश्न

Calculate the percentage of phosphorous in the fertilizer superphosphate, Ca(H2PO4)2. [Ca = 40, H =1, P =31, O = 16] (Correct to 1 decimal place)

योग
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उत्तर

Molecular mass of fertilizer superphosphate, Ca(H2PO4)2 =234
234 parts by weight of fertilizer contains 62 parts by weight of phosphorous
So, 100 parts will contain = 62 x 100/234 = 26.5‰

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अध्याय 5: Mole Concept and Stoichiometry - Exercise 5 [पृष्ठ ११९]

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फ्रैंक Chemistry Part 2 [English] Class 10 ICSE
अध्याय 5 Mole Concept and Stoichiometry
Exercise 5 | Q 6 | पृष्ठ ११९

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