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प्रश्न
Water can split into hydrogen and oxygen under suitable conditions. The equations representing the change is: 2H2O(I) → 2H2 (g) + O2(g)
Ammonia burns in oxygen and the combustion in the presence of a catalyst may be represented as:
2NH3 (g) +21/2O2 (g) → 2NO (g) + 3H2O (I)
What mass of steam is produced when 1.5 g of nitrogen monoxide is formed?
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उत्तर
Given equation is:
2NH3 (g) +21/2O2 (g) → 2NO (g) + 3H2O (I)
Molecular mass of NO = 30
Molecular mass of H2O = 18
From the equation :
2 moles of NO = 3 moles of H2O
60g of NO = 54g of H2O.
1.5g of NO = 54 x 1.5 / 60 = 1.35g of H2O.
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\[\ce{2NH3 + 2 1/2O2 -> 2NO + 3H2O}\] [H = 1, N = 14, O = 16]
What mass of steam is produced when 1.5 g of nitrogen monoxide is formed?
