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Calculate the number of atoms of each kind in 5.3 grams of sodium carbonate.

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Question

Calculate the number of atoms of each kind in 5.3 grams of sodium carbonate.

Numerical
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Solution

Molecular mass of Na2CO3 = 106 g

106 g has 2 x 6.02 x 1023 x 2 atoms of Na

So, 5.3g will have = `(6.02 xx 10^23 xx 2)/106 xx 5.3`

= 6.022 x 1022 atoms

Number of carbon atoms = `(6.02 xx 10^23)/106 xx53/10`

= 3.01 x 1022 atoms

And number of oxygen atoms = `(3 xx 6.02 xx 10^23)/106 xx 53/10`

= 9.03 x 1022

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Chapter 5: Mole concept and Stoichiometry - EXERCISE-5B [Page 84]

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S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
EXERCISE-5B | Q 17. | Page 84
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